x-3)(x+3)/2-(x+2)^2/2=x^2-3/6-1

Solution for x-3)(x+3)/2-(x+2)^2/2=x^2-3/6-1 equation:

x-3)(x+3)/2-(x+2)^2/2=x^2-3/6-1

We move all terms to the left:

x-3)(x+3)/2-(x+2)^2/2-(x^2-3/6-1)=0


Domain of the equation: 2-(x!=0

We move all terms containing x to the left, all other terms to the right

-(x!=-2

x∈R



Domain of the equation: 2-(x^2!=0

We move all terms containing x to the left, all other terms to the right

-(x^2!=-2

x∈R


We add all the numbers together, and all the variables

x-3)(x+3)/2-(x+2)^2/2-(x^2-3/6=0

We calculate fractions


x-3)(x-(x^2*6)/(-(x*2-(x^2*6+2)+2^2*2-(x*6)/(-(x*2-(x^2*6+2)+(-(x*2-(x^2-3*2)/(-(x*2-(x^2*6+2)+3*2=0

We can not solve this equation